题解 | #数字翻转#

#include <iostream>
#include <iterator>
#include <string>
#include <algorithm>
#include <climits>
using namespace std;

int rev(int x){
    string s= to_string(x);
    reverse(s.begin(), s.end());
 //判断是否溢出，溢出置0
    int max = INT_MAX;
    string t1 = to_string(INT_MAX);
    if(s.size()==t1.size() && s>t1) return 0;
    return stoi(s);
}


int main() {
    int a, b;
    cin>>a;
    cin>>b;
    cout<<rev(rev(a)+rev(b));
    return 0;
}