select job,sum(num) cnt from resume_info where date>='2025-01-01' and date<='2025-12-31' group by job order by cnt desc
思路:对num进行一个求和,对job进行分组,排序也按求和后的cnt
select job,sum(num) cnt from resume_info where date>='2025-01-01' and date<='2025-12-31' group by job order by cnt desc
思路:对num进行一个求和,对job进行分组,排序也按求和后的cnt