题解 | #简单计算器#

#include <stdio.h>
int main() 
{
	double a,b;
	char c;
	while(scanf("%lf%c%lf",&a,&c,&b)!=EOF)
	{
		if(c!='+'&&c!='-'&&c!='*'&&c!='/')
		{
			printf("Invalid operation!\n");
		}
		switch(c)
		{
			case '+':printf("%.4lf+%.4lf=%.4lf\n",a,b,a+b);break;
			case '-':printf("%.4lf-%.4lf=%.4lf\n",a,b,a-b);break;			
			case '*':printf("%.4lf*%.4lf=%.4lf\n",a,b,a*b);break;			
			case '/':
				if(b!=0)
				{
					printf("%.4lf/%.4lf=%.4lf\n",a,b,a/b);break;
				}
				else
				{
					printf("Wrong!Division by zero!\n");break;
				}
		}
	}
	return 0;
}