题解 | #得分不小于平均分的最低分#

select min(score) as min_score_over_avg
from exam_record
join examination_info using(exam_id)
where tag= 'SQL'
and score >= (
    select avg(score)
    from exam_record
    join examination_info using(exam_id)
    where tag = 'SQL'
)
#双and写法很意外

将min和avg分别书写