with
details as (
select
e.employee_id,
department_name,
performance_score,
avg(performance_score) over(partition by department_name) as avg_performance_score
from
employee_projects e
join department_info d on e.employee_id = d.employee_id
)
select employee_id
,department_name
,performance_score
from details d
where performance_score > avg_performance_score
order by employee_id



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