题解 | 整数的个位

const rl=require('readline').createInterface({input:process.stdin})
const iter=rl[Symbol.asyncIterator]()
const readline =async()=>(await iter.next()).value

void async function(){
    const lines=await readline()
    const a=parseInt(lines)
    if(a>=-10e9&&a<=10e9){
        console.log(a%10)
    }
    rl.close()
}()