题解 | 时间转换

#include <iostream>
using namespace std;

int main() {
    int seconds;
    int h, m, s;
    cin >> seconds;
    h = seconds / 3600;
    m = (seconds % 3600) / 60;
    s = seconds - h * 3600 - m * 60;
    cout << h << " " << m << " " << s << endl;

    return 0;
    
}
// 64 位输出请用 printf("%lld")