题解 | 数值的整数次方

class Solution {
public:
    double Power(double base, int exponent) {
        if(exponent>0)
        {
            double sum=1;
            for(int i=0;i<exponent;i++)
            {
                sum*=base;
            }
            return sum;
        }
        else if(exponent==0)
        {
            return 1.0;
        }
        else{
            base=1/base;
            double sum=1;
            for(int i=0;i<abs(exponent);i++)
            {
                sum*=base;
            }
            return sum;
        }
    }
};