题解 | #字符串分隔#

import sys

for line in sys.stdin:
    temp = list(line)
    result = []
    while len(temp) > 9:
        result.append(temp[0:8])
        for _ in range(8):
            temp.pop(0)
    result.append(temp[0:-1])

    # 以长度8作为拆分条件，只需要对最后一个元素补齐0
    if len(result[-1]) < 8:
        for _ in range(8 - len(result[-1])):
            result[-1].append('0')
            
    # 依次输出已分隔好的长度为8的字符串
    for i in result:
        print("".join(i))