题意:
题解:
AC代码
/* Author:zzugzx Lang:C++ Blog:blog.csdn.net/qq_43756519 */ #include<bits/stdc++.h> using namespace std; #define fi first #define se second #define pb push_back #define mp make_pair #define all(x) (x).begin(),(x).end() #define endl '\n' typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; const int mod=1e9+7; //const int mod=998244353; const double eps = 1e-10; const double pi=acos(-1.0); const int maxn=1e6+10; const ll inf=0x3f3f3f3f; const int dir[4][2]={{0,1},{1,0},{0,-1},{-1,0}}; ll n,m; ll a[maxn]; bool ok(ll x){ ll res=0; for(int i=1;i<=n;i++) if(a[i]<x)res+=x-a[i]; return res<=min(m,x); } int main() { ios::sync_with_stdio(false); cin.tie(0);cout.tie(0); //freopen("in.txt","r",stdin); //freopen("out.txt","w",stdout); cin>>n>>m; for(int i=1;i<=n;i++)cin>>a[i]; ll l=0,r=1e9,ans; while(l<=r){ ll mid=l+r>>1; if(ok(mid))ans=mid,l=mid+1; else r=mid-1; } cout<<ans; return 0; }