SELECT
exam_id,
duration,
release_time
FROM
(
SELECT
exam_id,
duration,
release_time,
fin_time,
TIMEDIFF(
fin_time,
lag( fin_time, 1 ) over ( PARTITION BY exam_id ORDER BY fin_time )) AS con,
0.5 * duration AS com
FROM
(
SELECT
info.exam_id,
info.duration,
info.release_time,
timediff( re.submit_time, re.start_time ) AS fin_time,
dense_rank() over ( PARTITION BY info.exam_id ORDER BY timediff( re.submit_time, re.start_time ) ) AS h_ranking,
dense_rank() over ( PARTITION BY info.exam_id ORDER BY timediff( re.submit_time, re.start_time ) DESC ) AS l_ranking
FROM
exam_record re
JOIN examination_info info ON re.exam_id = info.exam_id
WHERE
re.submit_time IS NOT NULL
) a
WHERE
h_ranking = 2
OR l_ranking = 2
ORDER BY
exam_id,
fin_time
) c
WHERE
MINUTE(con)+SECOND(con)/60 > com
ORDER BY
exam_id DESC;
exam_id,
duration,
release_time
FROM
(
SELECT
exam_id,
duration,
release_time,
fin_time,
TIMEDIFF(
fin_time,
lag( fin_time, 1 ) over ( PARTITION BY exam_id ORDER BY fin_time )) AS con,
0.5 * duration AS com
FROM
(
SELECT
info.exam_id,
info.duration,
info.release_time,
timediff( re.submit_time, re.start_time ) AS fin_time,
dense_rank() over ( PARTITION BY info.exam_id ORDER BY timediff( re.submit_time, re.start_time ) ) AS h_ranking,
dense_rank() over ( PARTITION BY info.exam_id ORDER BY timediff( re.submit_time, re.start_time ) DESC ) AS l_ranking
FROM
exam_record re
JOIN examination_info info ON re.exam_id = info.exam_id
WHERE
re.submit_time IS NOT NULL
) a
WHERE
h_ranking = 2
OR l_ranking = 2
ORDER BY
exam_id,
fin_time
) c
WHERE
MINUTE(con)+SECOND(con)/60 > com
ORDER BY
exam_id DESC;
首先通过dense_rank 窗口函数,对所有记录的答题时间进行排序;
然后我们筛选排名第二(h_ranking / l_ranking)的所有记录, 以答题时间(fin_time)进行升序排序
计算第二快和第二慢之间的时间差(con)
最后筛选下满足条件的记录。