题解 | #求解立方根#二分法和牛顿迭代法模板题，记住就行。

//二分法
#include <stdio.h>
int main() {
    float a;
    scanf("%f", &a);
    float left = -3, right = 3;
    while (left <= right) {
        float mid = (left + right) / 2;
        if (mid * mid * mid < a) left = mid + 0.01;
        else right = mid - 0.01;
    }
    printf("%.1f", left);
    return 0;
}
//牛顿迭代法
import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        float a = sc.nextFloat();
        float ans = a;
        while (Math.abs(ans * ans * ans - a) > 0.01) {
            ans -= (ans * ans * ans - a) / (ans * ans * 3);
        }
        System.out.printf("%.1f", ans);
    }
}
#Python版代码
number = float(input())
if number >= 0:print(f"{number ** (1 / 3):.1f}")
else:print(f"{-(-number) ** (1 / 3):.1f}")