题解 | #数位五五#

#include <stdio.h>

int main()
{
    int a = 0;
    int b = 0;
    scanf("%d %d", &a, &b);//输入
    int i = 0;
    int sum = 0;//数位之和
    int count = 0;//个数
    for (; a <= b; a++)//遍历每一个数
    {
        i = a;//存值
        sum = 0;//归零
        while (i)
        {
            sum += i % 10;
            i /= 10;
        }
        if (0 == sum % 5)//判断数位之和是否为5的倍数
        {
            count++;
        }
    }
    printf("%d\n", count);//输出
    return 0;
}