后序遍历,顺序为左子树,右子树,根节点;
二叉搜索树的大小排序为左<根<右
根节点一定在最后,根据左字数小于根节点,右子树大于根节点的特点,将左右子树找出,然后重复进行上述操作
public class Solution { public boolean VerifySquenceOfBST(int [] sequence) { if(sequence==null)return false; if(sequence.length==0)return false; return help(sequence, 0, sequence.length-1); } public boolean help(int [] sequence, int start, int end) { if(end&lt;=start)return true; int temp = sequence[end]; boolean flag = false; int key=start; for(int i=start;i&lt;end;i++){ if(!flag&amp;&amp;sequence[i]&gt;temp){ key = i; flag = true; } if(flag&amp;&amp;sequence[i]&lt;temp)return false; } return help(sequence, start, key-1)&amp;&amp;help(sequence, key, end-1); } }