题解 | #查找输入整数二进制中1的个数#

# print(bin(5)[2:].count('1'))

# n:int = int(input())
# print(bin(n)[2:].count('1'))
#
# while True:
#    try:
#        n: int = int(input())
#        print(bin(n).count("1"))
#    except:
#        break



while True:
    try:
        n: int = int(input())
        c: int = 0
        while n:
            if n % 2 == 1:
                c += 1
            n = n // 2
        print(c)
    except:
        break

注意多行输入的问题。