题解 | #坐标移动#

#include <iostream>
using namespace std;
#include<string>
#include<cmath>
int getNum(string str) {
    int num = 0;
    for (int i = str.size() - 1, j = 0; i >= 1 ; i--, j++) {
        if ('0' <= str[i] && str[i] <= '9' ) {
            num = num + (str[i] - '0') * (pow(10, j));
        } else {
            return -1;
        }
    }
    return num;
}

int main() {
    string str;
    int x = 0, y = 0;

    while (getline(cin, str, ';')) {
        switch (str[0]) {
            case 'A': {
                    if (getNum(str) != -1) {
                        x = x - getNum(str);
                    }

                    break;
                }
            case 'D': {
                    if (getNum(str) != -1) {
                        x = x + getNum(str);
                    }
                    break;
                }
            case 'W': {
                    if (getNum(str) != -1) {
                        y = y + getNum(str);
                    }
                    break;
                }
            case 'S': {
                    if (getNum(str) != -1) {
                        y = y - getNum(str);
                    }
                    break;
                }
            default: {
                    break;
                }



        }
    }
    cout << x << "," << y << endl;
}

使用 while (getline(cin, str, ';')) 这个语句读取以分号为结尾的字符串很好用，再简单写一个带报错的十进制字符串转int的函数就可以了