题解 | #尼科彻斯定理#

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while (sc.hasNextInt()) {
            int m = sc.nextInt();
            int sum = m * m * m;
            for(int i = 1;i<sum;i+=2){// 循环的数都为奇数
                StringBuilder sb = new StringBuilder();
                int tmp = 0;
                for(int j = 0;j<2*m;j+=2){// 循环m次，每次+2
                    tmp += (i+j);
                    sb.append( i + j + "+");
                }
                if(tmp == sum){
                    // 去掉最后一个+号
                    System.out.println(sb.deleteCharAt(sb.length()-1));
                }
            }
        }
    }
}