题解 | #3和5和7#

正常

#include<stdio.h>
int n;
int main(){
    scanf("%d",&n);
    for(int i=23;i<=n;i++){
        if((i%3==2)&&(i%5==3)&&(i%7==2)) printf("%d\n",i);
    }
}

摸完数据

#include<stdio.h>
int n;
int main(){
    scanf("%d",&n);
    for(int i=23;i<=n;i+=105){
        printf("%d\n",i);
    }
}