没人想到,把数字拼接成字符串 判断字符1的个数么?
好吧,面试可能会被虐
public class Solution {
public int NumberOf1Between1AndN_Solution(int n) {
String s = "";
int number = 0;
for(int i = 1; i<=n; i++){
s = s + i;
}
char[] cs = s.toCharArray();
for(int i = 0; i<cs.length; i++){
if(cs[i]=='1'){
number ++;
}
}
return number;
}
} 
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