题解 | 数颜色

#include <iostream>
#include <vector>
using namespace std;

int main() {
    int a, b;
    string str_rgb;
    cin >> str_rgb ;

    vector<int> num_rgb(3, 0);

    for (int i = 0; i < str_rgb.size(); i++) {
        if (str_rgb[i] == 'R') {
            num_rgb[0]++;
        } else if (str_rgb[i] == 'G') {
            num_rgb[1]++;
        } else if (str_rgb[i] == 'B') {
            num_rgb[2]++;
        } else {

        }
    }
    cout <<"("<<num_rgb[0]<<","<<num_rgb[1]<<","<<num_rgb[2]<<")"<<endl;

}
// 64 位输出请用 printf("%lld")