题解 | 字符串的反码

#include<bits/stdc++.h>
using namespace std;

char reverse(char a)
{
    if(a>='a'&&a<='z')
    {
        return 'z'-a+'a';
    }
    else if(a>='A'&&a<='Z')
    {
        return 'Z'-a+'A';
    }
    else {
    return a;
    }
}

int main()
{
    string str;
    while(cin>>str)
    {
        int len = str.length();
        for(int i = 0;i<len;i++)
        {
            str[i] = reverse(str[i]);
        }
        cout<<str<<endl;
    }

    return 0;
}