SELECT r.room_id, r.room_name, COUNT(DISTINCT u.user_id) AS user_count --避免同一用户多次进入同一直播间 FROM room_info_tb r INNER JOIN user_view_tb u ON r.room_id = u.room_id WHERE TIME(u.in_time) <= '24:00:00' --进入时间不晚于24:00(含24点) AND TIME(u.out_time) >= '23:00:00'--离开时间不早于23:00(含23点) GROUP BY r.room_id, r.room_name HAVING COUNT(DISTINCT u.user_id) > 0 ORDER BY user_count DESC



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