遍历一遍,看每个值出现的次数并且存在dict里就行。
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param numbers int整型一维数组
# @return int整型
#
class Solution:
def MoreThanHalfNum_Solution(self , numbers: List[int]) -> int:
# write code here
num_dict = {}
for i in range(len(numbers)):
if numbers[i] in num_dict:
num_dict[numbers[i]]+=1
else:
num_dict[numbers[i]]=1
for key , value in num_dict.items():
if value>len(numbers)/2:
return key