遍历一遍,看每个值出现的次数并且存在dict里就行。

#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 
# @param numbers int整型一维数组 
# @return int整型
#
class Solution:
    def MoreThanHalfNum_Solution(self , numbers: List[int]) -> int:
        # write code here
        num_dict = {}
        for i in range(len(numbers)):
            if numbers[i] in num_dict:
                num_dict[numbers[i]]+=1
            else:
                num_dict[numbers[i]]=1
        for key , value in num_dict.items():
            if value>len(numbers)/2:
                return key