解题思路就是使用哈希表结构按照顺序对字母进行计数。然后根据计数结果,首次出现的字母会被输出;没有只出现过一次的字母,打印-1
while True:
try:
s = input()
except:
break
letter = []
count_list = []
for c in s:
if c in letter:
count_list[letter.index(c)] += 1
else:
letter.append(c)
count_list.append(1)
try:
index = count_list.index(1)
print(letter[index])
except:
print(-1)