题解 | #完全数计算#

解题思路：
自定义一个完全数判断子函数，再遍历输出

def isPerNum(n):
    L = []
    L.append(1)
    for i in range(2,n):
        if n%i==0:
            L.append(i)
    return sum(L)==n

def test(n):
    j = 0
    for i in range(2,n+1):
        #print(i)
        if isPerNum(i):
            j += 1
    return j

while 1:
    try:
        n = int(input())
        print(test(n))
    except:
        break