题解 | #小乐乐改数字#

#include<stdio.h>
#include<math.h>
int main()
{
    int n = 0;
    int arr[10] = {0};
    int i = 0;
    int sum = 0;
    int tmp = 0;
    scanf("%d",&n);
    while(n)
    {
        tmp = n%10;
        if(tmp%2==0)
        {
            arr[i] = 0;
        }
        else
        {
            arr[i] = 1;
        }
        n=n/10;
        i++;
    }
    int j = 0;
    for(j = 0;j<i;j++)
    {
        sum = sum+arr[j]*pow(10,j);
    }
    printf("%d",sum);
    return 0;
}