题解 | 拍照队形

#include <iostream>
#include <string>
using namespace std;

int main() {
    int a=0, b;
    int N;
    cin >> N;
    string str_people;
    cin.ignore();
    getline(cin, str_people);
    //cin >> str_people;
    //cout << str_people.c_str();
    //cout << str_people.size();
    int K = (N - 1) / 3;
    //cout << K << endl;
    int i = 0;
    while (i < (2 * K + 1) ) { // 注意 while 处理多个 case
        if (i < K) {
            for (int m=0; m<i; m++) {
                cout << " " ;
            }
            cout << str_people[2*i];
            int j = 0;
            while (j < (2 * K - 1 - 2*i)) {
                cout << " " ;
                j++;
            }
            cout << str_people[2*i+1]<<endl;
            i++;
        }
        
        if (i>=K && ( i+K < str_people.size() )) {
            int j = 0;
            while (j < K) {
                cout << " ";
                j++;
            }
            cout << str_people[i+K] <<endl;
            i++;
            //cout <<"i="<<i<<"j="<<j<<endl;
        }

    }
    return 0;
}
// 64 位输出请用 printf("%lld")