题解 | 求四位数各个数位之和

#include <stdio.h>

int main() {
    int n,a,b,c,d,sum;
    scanf("%d",&n);
    a = n / 1000;
    b = (n - a * 1000) / 100;
    c = (n- a * 1000 - b * 100) / 10;
    d = (n - a * 1000 - b * 100 - c * 10);
    sum = a + b + c + d;
    printf("%d",sum);
    return 0;
}