题解 | #包含数字9的数#

#include<stdio.h>
int main()
{
	int year = 2019;
	int i,j,count =0;
	for(i=1;i<=year;i++)
	{
		if(i%10==9)
		{
			count++;
		}
		else if((i/10)%10 == 9)
		{
			count++;
		}
		else if((i/100)%10 ==9)
		{
			count++;
		}
	}
	printf("%d",count);
	return 0;
}