题解 | #数字反转之-三位数#

#include <stdio.h>

int main(void)
{
    int n, a[3], b;
    scanf("%d",&n);
    if(100 <= n && n <= 999)
    {
        a[0] = n/100;
        a[2] = n%10;
        a[1] = n%100;
        a[1] = a[1]/10;
        if(a[2] == 0){
            if(a[1] == 0){
                printf("%03d", a[0]);
            }
            else{
                b = a[1]*10 + a[0];
                printf("%03d", b);   
            }
        }
        else{
            b = a[2]*100 + a[1]*10 + a[0];
            printf("%d", b);   
        }
    }
    return 0;
}

初次尝试，望各位大佬指正