# 函数自定义

#第一种
def Sum(x,y):
    return x+y

#第二种
sum =lambda x,y:x+y
num =lambda x:x[0]
res=Sum(1,2)
res_=sum(2,3)
print(res)
print(res_)
print(num(['hello bigdate',0]))

#求序列偶数的个数
def su(x):
    ans=0
    for i in x:
        if i%2==0:
            ans+=1
    return ans

res=su([1,2,3,4,5,6,7])
print(res)