看错题目了,没注意是当小于5的时候也是回归到整数,这时候向下取整
#include<bits/stdc++.h>
using namespace std;#define int long long
#define endl '\n'
void solve(){
int n;
cin>>n;
if(n%10>=5)
{
int m=10-n%10;
cout<<n+m<<endl;
}
else cout<<n-n%10<<endl;
}
signed main(){
std::ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
solve();
return 0;
}