题解 | 日期差值

#include<stdio.h>
using namespace std;

void nextday(int& year, int& month, int& day) {
    int dayofmonth[] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    //先判断是否闰年，闰年的2月是29天
    if ((year % 400 == 0) || (year % 100 != 0 && year % 4 == 0))dayofmonth[2] = 29;
    //如果天数超出
    if ((day + 1) > dayofmonth[month]) {
        //如果月份超出
        if ((month + 1) > 12) {
            year++;
            month = 1;
            day = 1;
        } else {
            month++;
            day = 1;

        }

    } else day++;
}

int main(){
    int date1,year1,month1,day1;
    int date2,year2,month2,day2;
    scanf("%d\n",&date1);
    scanf("%d",&date2);
    day1=date1%100;
    month1=date1/100%100;
    year1=date1/10000;
    day2=date2%100;
    month2=date2/100%100;
    year2=date2/10000;
    int cnt=1;
    while(true){
        nextday(year1,month1,day1);
        cnt++;
        if(year1==year2&&month1==month2&&day1==day2)break;
    }
    printf("%d",cnt);



    return 0;
}