题解 | 计算一年中的第几天

#include <bits/stdc++.h>
using namespace std;
int days[13]={3,31,28,31,30,31,30,31,31,30,31,30,31};
bool isLeapYear(int year)
{
    return (year%4==0 && year%100!=0) || (year%400==0);
}
int getDays(int year,int month)
{
    return (isLeapYear(year) && month==2)?29:days[month];
}
int main() {
   int year=0,month=0,day=0;
   while(cin>>year>>month>>day)
   {
   int sum=0;
    for(int i=1;i<month;i++)
    {
        sum+=getDays(year,i);
    }
    sum+=day;
    cout<<sum<<endl;
   }
}
// 64 位输出请用 printf("%lld")