题解 | 迷路的牛牛

#include<iostream>
#include<string>
using namespace std;

int main() {
	char F[4] = { 'N','E','S','W' };
	long long m = 0;
	long long n;
	string s;
	cin >> n;
	cin.ignore();
	getline(cin, s);
	for (long long i = 0; i < n; i++) {
		if (s[i] == 'L') {
			m--;
		}
		else if (s[i] == 'R') {
			m++;
		}
	}
	if (m >= 0) {
		m = m % 4;
	}
	else {
		m = m % 4 + 4;
	}
	m = m % 4;
	cout << F[m] << endl;
	return 0;
}