同上一题,正数看作1,负数看作-1,k=0
m存储前i项和对应下标,a存储前i项和,ans最大长,即求第i项时m[a-k]是否存在
def solve(l, n):
m = {0:-1}
a = ans = 0
for i in range(n):
if l[i] > 0:
a += 1
elif l[i] < 0:
a -= 1
if a not in m.keys():
m[a] = i
else:
ans = max(ans, i - m[a])
return ans
while True:
try:
n = int(input())
l = list(map(int, input().split()))
print(solve(l, n))
except EOFError:
break
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