#include <stdio.h>
//包含数字9的数
int main()
{
    int m = 0;
    int i = 0;
    int n = 0;
    for (i =1; i <= 2019; i++)
    {
        n = i;
        while (n)
        {
            if (n % 10 == 9)
            {
                m++;
                break;
            }
            n /= 10;
        }
    }
    printf("%d\n",m);

    return 0;
}