题解 | #约数的个数#

#include <stdio.h>

int main() {
    int a;
    while (scanf("%d", &a) != EOF) { // 注意 while 处理多个 case
        // 64 位输出请用 printf("%lld") to
        int arr[a];
        int count[a];
        for (int i=0;i<a;i++){
            scanf("%d", &arr[i]);
            count[i] = 0;
        }
        for (int i=0;i<a;i++){
            for (int j=1;j*j<=arr[i];j++){
                if (j * j == arr[i]){
                    count[i] ++;
                }else{
                    if (arr[i] % j == 0){
                        count[i] += 2;
                    }
                }
            }
        }
        for (int i=0;i<a;i++){
            printf("%d\n", count[i]);
        }
    }
    return 0;
}