select name,date,sum(number) over(partition by user_id order by date) from passing_number left join user u on u.id=user_id order by date,name
使用窗口函数就很容易实现,根据题意,login表根本不用管他
select name,date,sum(number) over(partition by user_id order by date) from passing_number left join user u on u.id=user_id order by date,name
使用窗口函数就很容易实现,根据题意,login表根本不用管他