利用倍增数组,记录:
- B[i][j]: 从下标
开始,向后走
步会走到哪个下标
- C[i][j]: 从下标
开始,向后走
步经过的所有数之和对
取模的结果
'''
Hala Madrid!
https://github.com/USYDDonghaoLi/Programming_Competition
'''
import sys
import os
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
def I():
return input()
def II():
return int(input())
def MI():
return map(int, input().split())
def LI():
return list(input().split())
def LII():
return list(map(int, input().split()))
def GMI():
return map(lambda x: int(x) - 1, input().split())
#------------------------------FastIO---------------------------------
from bisect import *
from heapq import *
from collections import *
from functools import *
from itertools import *
from time import *
from random import *
from math import log, gcd, sqrt, ceil
inf = float('inf')
fmin = lambda x, y: x if x < y else y
fmax = lambda x, y: x if x > y else y
mod = 10 ** 9 + 7
# @TIME
def solve(testcase):
n, k, q = MI()
A = LII()
assert len(A) == n
B = [[-1 for _ in range(n)] for _ in range(60)]
for i in range(n):
nxt = (i + k) % n
B[0][i] = nxt
for i in range(1, 60):
for j in range(n):
B[i][j] = B[i - 1][B[i - 1][j]]
C = [[-1 for _ in range(n)] for _ in range(60)]
for i in range(n):
nxt = B[0][i]
C[0][i] = A[nxt]
for i in range(1, 60):
for j in range(n):
nxt = B[i - 1][j]
C[i][j] = (C[i - 1][j] + C[i - 1][nxt]) % mod
for i in range(q):
t, step = MI()
t -= 1
res = 0
for bit in range(60):
if step >> bit & 1:
# print("t", t)
res = (res + C[bit][t]) % mod
t = B[bit][t]
print(res)
for testcase in range(1):
solve(testcase)

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