There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:

(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l’ and weight w’ if l<=l’ and w<=w’. Otherwise, it will need 1 minute for setup.

You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2).
Input
The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1<=n<=5000, that represents the number of wooden sticks in the test case, and the second line contains n 2 positive integers l1, w1, l2, w2, …, ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.

Output
The output should contain the minimum setup time in minutes, one per line.

Sample Input

3 
5 
4 9 5 2 2 1 3 5 1 4 
3 
2 2 1 1 2 2 
3 
1 3 2 2 3 1

Sample Output

2
1
3

好烦啊。。。
其他的题也有类似的情况，样例能过但是提交错误。。。
但是这个实在看不出，数组开的刚好够大，也尝试分组输出和同时输出，为什么就不能过呢。。。确实一开始写的有点问题，木棍的长度和重量必须同时满足条件才可以，但是。。。
两类代码(WA)：
一、

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
int c[5001];
using namespace std;
struct wooden
{

    int l,w;

};
wooden my[5010];
bool comp(wooden a,wooden b)
{
    if(a.l>b.l)
        return 1;
    else if(a.l==b.l)
        return a.w>b.w;
    else
        return 0;
}
int main()
{
    int t;
    cin>>t;
    int x=1;
    while(t--)
    {
        int n;
        cin>>n;
        int i=0,j;
        while(i<n)
            cin>>my[i++].l>>my[i].w;
        sort(my,my+n,comp);
        int out=n;
        for(i=1; i<n; i++)
            for(j=0; j<=i-1; j++)
            {
                if(my[j].l>=my[i].l&&my[j].w>=my[i].w)
                {
                    out--;
                    my[j].l=my[i].l;
                    my[j].w=my[i].w;
                    my[i].l=0;
                    my[i].w=0;
                    break;
                }
            }
            c[x]=out;
            x++;
    }
    for(int i=1;i<x;i++)
        cout<<c[i]<<endl;
    return 0;
}

二、

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
using namespace std;
struct wooden
{

    int l,w;

};
wooden my[5010];
bool comp(wooden a,wooden b)
{
    if(a.l>b.l)
        return 1;
    else if(a.l==b.l)
        return a.w>b.w;
    else
        return 0;
}
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n;
        cin>>n;
        int i=0,j;
        while(i<n)
            cin>>my[i++].l>>my[i].w;
        sort(my,my+n,comp);
        int out=n;
        for(i=1; i<n; i++)
            for(j=0; j<=i-1; j++)
            {
                if(my[j].l>=my[i].l&&my[j].w>=my[i].w)
                {
                    out--;
                    my[j].l=my[i].l;
                    my[j].w=my[i].w;
                    my[i].l=0;
                    my[i].w=0;
                    break;
                }
            }
        cout<<out<<endl;
    }
    return 0;
}