题解 | 好串

#include <bits/stdc++.h>
using namespace std;
int main()
{
	string s;
	cin >> s;
	int cnt1 = 0;
	int cnt2 = 0;
	for (int i = 0; i < s.size(); i++)
	{
		if (s[i] == 'a')
			cnt1++;
		else
			cnt2++;
        if(cnt2 > cnt1)
        {
            cout<<"Bad";
            return 0;
        }
	}
	if(cnt1 != cnt2)
    cout<<"Bad";
    else
    cout<<"Good";
	return 0;
}

不会写栈喵