题解 | 左侧严格小于计数

import sys

n = int(sys.stdin.readline().strip())
l = list(map(int, sys.stdin.readline().split()))
counts = [0] * 11

for num in l:
    # 计算前面比当前元素小的元素总数
    smaller_count = sum(counts[:num])
    print(smaller_count, end=' ')
    counts[num] += 1