这道题比前一个更复杂一点,计算难度增加了,不仅得计算正确数,还得计算准确率=正确数/总回答数 select qd.difficult_level, sum(case when qpd.result='right' then 1 else 0 end)/count(*) as correct_rate from question_practice_detail as qpd left join question_detail as qd on qpd.question_id=qd.question_id join user_profile as up on qpd.device_id=up.device_id and up.university='浙江大学' group by qd.difficult_level order by correct_rate;