判断奇数和偶数的个数是否合法。
#include<bits/stdc++.h>
#define int long long
#define double long double
#define x first
#define y second
using namespace std;
typedef long long LL;
typedef long long ll;
typedef pair<int, int> PII;
const int N = 3e5 + 10;
const int M = 1e3 + 10;
int mod = 1e9 + 7;
int a[N];
void solve() {
int c1 = 0, c2 = 0;
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
int x;
cin >> x;
if (x % 2) c1++;
else c2++;
}
if (c1 >= 3 || (c1 >= 1 && c2 >= 2)) cout << "YES\n";
else cout << "NO\n";
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
int _;
_ = 1;
//cin>>_;
while (_--) {
solve();
}
}

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