题解 | 时间转换

#include <stdio.h>

int main() 
{
    int a,b,c;
    int  sum;
    scanf("%d",&a);
   
    sum=a/3600;
    b =a%3600/60;
    c =a%3600%60;


        printf("%d %d %d", sum,b,c);
    
    return 0;
}