解法1:模拟
public ListNode partition (ListNode head, int x) { // write code here ListNode small=new ListNode(0); ListNode smallHead=small; ListNode large=new ListNode(0); ListNode largeHead=large; while(head!=null){ if(head.val<x){ small.next=head; small=small.next; } else{ large.next=head; large=large.next; } head=head.next; } large.next=null; small.next=largeHead.next; return smallHead.next; }