牛客网真题2019-26-数组组合

两个数组各自一个游标指针，按位添加到结果数组
注意第二行字符串可能为空串，关键空串Scanner读不到，需要判断是否有next
推荐一波stream流式编程，java玩出python的感觉。

package org.niuke.solution26;

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        String str = sc.nextLine();
        if(!sc.hasNext()){
            System.out.println(str);
            return;
        }
        String[] s1 = str.split(",");
        String[] s2 = sc.nextLine().split(",");
        int[] ints1 = Arrays.stream(s1).mapToInt(Integer::parseInt).toArray();
        int[] ints2 = Arrays.stream(s2).mapToInt(Integer::parseInt).toArray();
        int p1 = 0, p2 = 0;
        int[] s = new int[s1.length + s2.length];
        while (p1 < ints1.length || p2 < ints2.length) {
            if(p1 < ints1.length && p2 < ints2.length){
                if(ints1[p1] <= ints2[p2]){
                    s[p1 + p2] = ints1[p1];
                    p1++;
                }else{
                    s[p1 + p2] = ints2[p2];
                    p2++;
                }
            }else if(p1 < ints1.length){
                s[p1 + p2] = ints1[p1];
                p1++;
            }else{
                s[p1 + p2] = ints2[p2];
                p2++;
            }
        }
        for(int i = 0; i < s.length; i++){
            if(i < s.length - 1){
                System.out.print(s[i] + ",");
            }else{
                System.out.print(s[i]);
            }

        }
    }
}