遍历求和
#include <iostream>
using namespace std;
int main()
{
int T;
cin >> T;
while (T--)
{
int n, w, c;
cin >> n >> w >> c;
int wc[2 * n];
for (int i = 0; i < 2 * n; i++)
{
cin >> wc[i];
}
int wtotal = 0, ctotal = 0;
for (int i = 0; i < n; i++)
{
wtotal += wc[i];
ctotal += wc[i + n];
}
if (wtotal > w || ctotal > c)
{
cout << "NO" << endl;
}
else
{
cout << "YES" << endl;
}
}
return 0;
}


京公网安备 11010502036488号