#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param s string字符串 
# @param c string字符串 
# @return int整型
#
class Solution:
    def isCongruent(self , s: str, c: str) -> int:
        # write code here
        arr1=[0]*26
        arr2=[0]*26
        for  ch in s:
            arr1[ord(ch)-ord('a')]+=1
        
        for  ch in c:
            arr2[ord(ch)-ord('a')]+=1 
        count=0
        for i in  range(len(arr1)):
            if arr1[i]!=arr2[i]:
                return  -1
            else:
                count+=arr1[i]  # 统计次数
        return   count